Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - Chapter Review - Page 654: 28

Answer

$=30t^4\sqrt 3$

Work Step by Step

$6\sqrt 5t^3.\sqrt 15t^5$ $=6\sqrt 75t^8$ $=6*5t^4\sqrt 3$ $=30t^4\sqrt 3$
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