## Algebra 1: Common Core (15th Edition)

The hypotenuse is 2.6 and one of the legs is 1. Find the other leg using $a^{2}$+$b^{2}$=$c^{2}$. Plug in the leg for A and the hypotenuse for C: $a^{2}$+$b^{2}$=$c^{2}$ $1^{2}$+$b^{2}$=$2.6^{2}$ -simplify the exponents- 1 + $b^{2}$=6.76 -subtract 1 from both sides- $b^{2}$=5.76 -find the square root of 5.76 in order to solve for b- b=2.4 The other leg is 2.4.