## Algebra 1: Common Core (15th Edition)

The answer is $-(2\sqrt5+5)$
We can simplify the expression as follows: $= \sqrt5/(2-\sqrt5)$ $= \sqrt5/(2-\sqrt5)*(2+\sqrt5)/(2+\sqrt5)$ $= \sqrt5*(2+\sqrt5)/(2^{2}-\sqrt5^{2})$ $= (2\sqrt5+(\sqrt5)^{2})/(4-5)$ $= (2\sqrt5+5)/(-1)$ $= -(2\sqrt5+5)$