Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 33


The answer is $-(2\sqrt5+5)$

Work Step by Step

We can simplify the expression as follows: $= \sqrt5/(2-\sqrt5)$ $= \sqrt5/(2-\sqrt5)*(2+\sqrt5)/(2+\sqrt5)$ $= \sqrt5*(2+\sqrt5)/(2^{2}-\sqrt5^{2})$ $= (2\sqrt5+(\sqrt5)^{2})/(4-5)$ $= (2\sqrt5+5)/(-1)$ $= -(2\sqrt5+5)$
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