Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 15

Answer

$-7\sqrt 5$

Work Step by Step

You are given $3\sqrt 45$ $-$ $8\sqrt 20$.Simplify: Factor perfect squares out of the radicands: $3 \sqrt 9*5$ $-$ $8 \sqrt 4*5$ Multiplication property: $3 (\sqrt 9) ({\sqrt 5})$ $-$ $8 (\sqrt 4) ({\sqrt 5})$ $3(3) (\sqrt 5)$ $-$ $8(2) (\sqrt 5)$ $9\sqrt 5$ $-$ $16\sqrt 5$ $\sqrt 5(9-16)$ =$-7\sqrt 5$
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