## Algebra 1: Common Core (15th Edition)

The answer is $-\sqrt6$.
We can simplify the expression as follows: $=(\sqrt6+\sqrt3)(\sqrt2-2)$ $=\sqrt6*\sqrt2-\sqrt6*2+\sqrt3*\sqrt2-\sqrt3*2$ $=\sqrt12-2\sqrt6+\sqrt6-2\sqrt3$ $=(\sqrt4*\sqrt3)-\sqrt6-2\sqrt3$ $=2\sqrt3-\sqrt6-2\sqrt3$ $=-\sqrt6$.