Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 21


$2\sqrt3+3\sqrt 2$

Work Step by Step

We can simplify the product as follows: = $\sqrt 6(\sqrt 2+\sqrt 3)$ = $(\sqrt 2*\sqrt3)(\sqrt 2+\sqrt 3)$ = $(\sqrt 2*\sqrt3)*\sqrt 2+(\sqrt 2*\sqrt3)*\sqrt 3$ = $2\sqrt3+3\sqrt 2$ (since $\sqrt x * \sqrt y = \sqrt xy$)
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