## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 26

#### Answer

The answer is $106+6\sqrt77$.

#### Work Step by Step

We can simplify the expression as follows: $=(3\sqrt11+\sqrt7)^{2}$ $=(3\sqrt11+\sqrt7)*(3\sqrt11+\sqrt7)$ $=(3\sqrt11)^{2}+(\sqrt7)^{2}+2*3\sqrt11*\sqrt7$ (Since $(a+b)^{2}=a^{2}+b^{2}+2ab)$ $=(3\sqrt11)*(3\sqrt11)+(\sqrt7)*(\sqrt7)+2*3\sqrt11*\sqrt7$ $=(9*11)+7+6\sqrt77$ $=99+7+6\sqrt77$ $=106+6\sqrt77$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.