Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 629: 29


The answer is $62-20\sqrt6$.

Work Step by Step

We can simplify the expression as follows: $=(5\sqrt2-2\sqrt3)^{2}$ $=(5\sqrt2)^{2}+(2\sqrt3)^{2}-2*5\sqrt2*2\sqrt3$ (since $(a-b)^{2}=a^{2}+b^{2}-2ab)$ $=(25*2)+(4*3)-20\sqrt6$ $=50+12-20\sqrt6$ $=62-20\sqrt6$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.