## Algebra 1: Common Core (15th Edition)

$y=\frac{2 \pm \sqrt 10}{3}$
$3y^2-4y-2=0$ Using the quadratic formula: $y=\frac{-(-4) \pm \sqrt (-4)^2-4.3.(-2)}{2.3}$ $y=\frac{4 \pm 2\sqrt 10}{6}$ $y=\frac{2 \pm \sqrt 10}{3}$