Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 624: 72

Answer

$y=\frac{2 \pm \sqrt 10}{3}$

Work Step by Step

$3y^2-4y-2=0$ Using the quadratic formula: $y=\frac{-(-4) \pm \sqrt (-4)^2-4.3.(-2)}{2.3}$ $y=\frac{4 \pm 2\sqrt 10}{6}$ $y=\frac{2 \pm \sqrt 10}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.