Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 624: 73

Answer

$3, 12, 27$

Work Step by Step

Let $x$ be the number whose square root is of the form $a\sqrt3$ $\implies \sqrt x = a \sqrt3$ Squaring both sides $x = a^2 \times 3$ Now we can generate any 3 numbers by replacing a with any real number. Replacing $a$ with 1 we get x as: $x = 3$ Replacing $a$ with 2 we get x as: $x = 4\times 3 = 12$ Replacing $a$ with 3 we get x as: $x = 9 \times 3 = 27$
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