## Algebra 1: Common Core (15th Edition)

$8\sqrt 6a / 3a$
We can simplify the expression as follows: = $16a / \sqrt 6a^{3}$ = $16a / (\sqrt 6*\sqrt a^{2}*\sqrt a)$ = $16a / (\sqrt 6*a*\sqrt a)$ = $16 / (\sqrt 6*\sqrt a)$ = $16*(\sqrt 6*\sqrt a) / (\sqrt 6*\sqrt a)*(\sqrt 6*\sqrt a)$ (Multiply and divide by $(\sqrt 6*\sqrt a)$ to rationalize the denominator). = $16*(\sqrt 6a) / 6a$ = $8\sqrt (6a) / 3a$.