Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 624: 64


$-\sqrt 3$

Work Step by Step

Rationalize the denominator by multiplying $\sqrt 6$ to the numerator and denominator. $\frac{-3\sqrt 2}{\sqrt 6}\times\frac{\sqrt 6}{\sqrt 6}$ Simplify $\frac{-3\sqrt 12}{6}$ $\frac{-3\sqrt 4\times\sqrt 3}{6}$ $\frac{-3\times2\sqrt 3}{6}$ $\frac{-6\sqrt 3}{6}$ $-\sqrt 3$ Answer: $-\sqrt 3$
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