Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 624: 54

Answer

Correct answer: $\sqrt \frac{x}{5} = \frac{\sqrt x}{\sqrt 5}$

Work Step by Step

$Mistake$: student brought out $x$ without a square root. According to the property: $\sqrt (a \times b) = \sqrt a \times \sqrt b$ The numerator should be: $\sqrt (5 \times x) = \sqrt 5 \times \sqrt x$ Hence, the correct answer is: $\frac{\sqrt 5 \times \sqrt x}{\sqrt 25}$ $\frac{\sqrt 5 \times \sqrt x}{\sqrt 5 \times \sqrt 5}$ $= \frac{\sqrt x}{\sqrt 5}$
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