Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.34b

Answer

The wavelength of this light is $286.3nm$.

Work Step by Step

The wavelength of this light would be calculated according to the formula $$c=\lambda\times\nu$$ - Frequency of this light: $\nu\approx1.047\times10^{15}s^{-1}$ - Speed of light in a vacuum: $c\approx2.998\times10^8m/s$ Therefore, the wavelength of this light would be: $\lambda=\frac{c}{\nu}=\frac{2.998\times10^8}{1.047\times10^{15}}\approx2.863\times10^{-7}m\approx286.3nm$
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