Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.26a

Answer

The frequency of that light is $5.635\times10^{14}s^{-1}$.

Work Step by Step

*Strategy: To find frequency when you already know the wavelength of radiation, you should follow this formula $$c=\lambda\times\nu$$ $c$ : speed of light in vacuum (therefore, $c\approx2.998\times10^{8}m/s$) $\lambda$: wavelength of radiation $\nu$: frequency of radiation - Step 1: Find the known variables A pointer emits light with a wavelength of $532nm$; therefore, $\lambda=532nm=5.32\times10^{-7}m$. - Step 2: Find the frequency ($\nu$) of that light $\nu=\frac{c}{\lambda}=\frac{2.998\times10^8}{5.32\times10^{-7}}\approx5.635\times10^{14}s^{-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.