Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.25a

Answer

The energy of a single photon of this electromagnetic radiation is $1.948\times10^{-19}J$.

Work Step by Step

*Strategy: We would use the following formula of Planck's theory $E = h\times\nu$ $E$ : the energy of a single quantum (or in this case, photon) $h$ : Planck constant ($h\approx6.626\times10^{-34}J.s$) $\nu$ : frequency of radiation Step 1: Find the known variables We know the electromagnetic radiation has frequency of $2.94\times10^{14}s^{-1}$; so $\nu=2.94\times10^{14}s^{-1}$ Step 2: Do the calculation according to the formula The energy of a single photon of this electromagnetic radiation is: $E=h\times\nu=(6.626\times10^{-34})\times(2.94\times10^{14})\approx1.948\times10^{-19}J$
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