Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.26b

Answer

The energy of a photon of that light is $3.734\times10^{-19}J$.

Work Step by Step

*Strategy: To find the energy of a photon of that light requires the use of the following formula $$E=h\times\nu$$ $E$ : the energy of a photon of that light $h$ : Planck constant ($h=6.626\times10^{-34}J.s$) $\nu$ : frequency of that light - Step 1: Find the known variables We figure out the frequency of that light in part a): $\nu\approx5.635\times10^{14}s^{-1}$ - Step 2: Calculate the energy of a photon of that light $E=h\times\nu=(6.626\times10^{-34})\times(5.635\times10^{14})\approx3.734\times10^{-19}J$.
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