Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.19b

Answer

$545nm$

Work Step by Step

*Strategy: using the formula $$\lambda\times\nu=c$$ in which $\lambda$ : wavelength of radiation $\nu$ : frequency of radiation $c$ : speed of light (we take the speed of light in vacuum, so $c \approx 2.998 \times 10^8m/s$) - Step 1: We know the radiation has a frequency of $5.50\times10^{14}s^{-1}$, so $\nu=5.50\times10^{14}s^{-1}$ - Step 2: Calculate the wavelength of radiation ($\lambda$) $\lambda=\frac{c}{\nu}=\frac{2.998\times10^8m/s}{5.50\times10^{14}s^{-1}}\approx0.545\times10^{-6}m\approx545nm$
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