Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises - Page 250: 6.19a

Answer

$2.998 \times 10^{13}s^{-1}$

Work Step by Step

*Strategy: using the formula $$\lambda\times\nu=c$$ in which $\lambda$ : wavelength of radiation $\nu$ : frequency of radiation $c$ : speed of light (we take the speed of light in vacuum, so $c \approx 2.998 \times 10^8m/s$) - Step 1: we know the radiation has a wavelength of $10\mu m$, so $\lambda = 10\mu m = 10^{-5}m$ (remember that $c$ and $\lambda$ must be in compatible units to do the calculation). - Step 2: Calculate frequency of radiation ($\nu$) $\nu = \frac{c}{\lambda} = \frac{2.998\times10^{8}m/s}{10^{-5}m} \approx 2.998\times10^{13} (s^{-1})$ That's the answer you need.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.