Chemistry: The Central Science (13th Edition)

From this formula $$E=\frac{h\times c}{\lambda}$$ we see that $E$ and $\lambda$ are inversely proportional. Therefore, any radiation with wavelength $\lambda\lt286.3nm$ would produce photons of energy $E\gt6.94\times10^{-19}J$, the minimum energy $(E_{min})$ needed to eject electrons from titanium surface. In other words, to eject electrons from titanium surface requires a radiation with wavelength less than $286.3nm$. The wavelength range of visible light is from $400nm$ to $750nm$. Therefore, visible light could not eject electrons from titanium surface.