Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.31b

Answer

The number of photons per second is emitted by the laser: $8.073\times10^{16}photons/s$.

Work Step by Step

*Strategy: 1) Calculate the energy of a photon of this radiation. 2) Find out how much energy is absorbed per second by the detector. 3) Calculate the number of photons emitted by the laser per second. 1) Calculate the energy of a photon of this radiation. *Known variables and constants: - Wavelength of radiation: $\lambda=9.87\times10^{-7}m$ - Planck's constant: $h\approx6.626\times10^{-34}J.s$ - Speed of light in a vacuum: $c\approx2.998\times10^8m/s$ *The energy of a photon of this radiation is: $E_p=\frac{h\times c}{\lambda}=\frac{(6.626\times10^{-34})\times(2.998\times10^8)}{9.87\times10^{-7}}\approx2.013\times10^{-19}J/photons$ 2) Find out how much energy is absorbed by the detector per second. *Known variables: - Total energy absorbed: $E=0.52J$ - Amount of time: $t=32s$ *The amount of energy absorbed per second is: $E_s=\frac{E}{t}=\frac{0.52}{32}=1.625\times10^{-2}J/s$ 3) Calculate the number of photons ($N$) emitted by the laser per second. $N=\frac{E_s}{E_p}=\frac{1.625\times10^{-2}}{2.013\times10^{-19}}\approx8.073\times10^{16}photons/s$
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