Answer
$1.5\times10^4m$
Work Step by Step
*Strategy: We would use the classic formula of the relationship between distance, time and velocity:
$v\times t=x$
in which
$v$: velocity of object
$t$: the time the object travels
$x$: the distance the object covers during the time $t$ and with velocity $x$
- Step 1: Find the known quantities
We know that electromagnetic radiation always travels with the speed of light in vacuum, so $v = c \approx 2.998\times10^8m/s$
We also know that the electromagnetic radiation travels in $50.0\mu s$, so $t = 50.0\mu s = 5\times10^{-5}s$ (remember to change the unit to second ($s$) to be compatible with $v$ for calculation)
- Step 2: Do the calculation
The distance the electromagnetic radiation travels is
$x=v\times t= (2.998\times10^8)\times(5\times10^{-5})\approx1.5\times10^4m$
