Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 9

Answer

$1.1674$

Work Step by Step

Use a scientific calculator, we have $log_9(13)=\frac{log13}{log9}\approx1.1674$
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