Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 8

Answer

$\pm125$

Work Step by Step

Given $x^{2/3}=25$, raise both side to 3rd power to get $x^2=(25)^3$, take square root on both sides, we have $x=\pm(5)^3=\pm125$
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