Answer
$12.548$
Work Step by Step
Take $log$ on both sides to get $(x+1)log2=(x-4)log3\longrightarrow x\ log2+log2=x\ log3-4log3\longrightarrow (log3-log2)x=log2+4log3$, thus $x=\frac{log2+4log3}{log3-log2}\approx12.548$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 14
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