Answer
$39.2\ yrs$
Work Step by Step
Use $A=Pe^{rt}$ with $r=0.028, A=3P$, we have $3P=Pe^{0.028t} \longrightarrow e^{0.028t}=3 \longrightarrow 0.028t=ln(3)$, thus $t=\frac{ln(3)}{0.028}\approx39.2\ yrs$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 25
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