Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 19

Answer

$x=2$

Work Step by Step

1. Use product rule, we have $log_2[x(x+2)]=3\longrightarrow x(x+2)=2^3\longrightarrow x^2+2x-8=0\longrightarrow (x+4)(x-2)=0$, thus $x=-4,2$ 2. Check the answers in the original equation, we find only $x=2$ fits.
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