Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 7

Answer

(a) $ 3.3780$ (b) $ 7.7782$ (c) $ 1.1674$

Work Step by Step

Use a scientific calculator with $log$ and $ln$ functions, we have: (a) $log2388\approx3.3780$ (b) $ln2388\approx7.7782$ (c) $log_9(13)=\frac{log13}{log9}\approx1.1674$
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