Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 22

Answer

See explanations.

Work Step by Step

By definition $log_5(27)=x$ means $5^x=27$, that is the logarithm is the exponent needed to raise the power of a base $5$ to get $27$. As $log_5(27)=\frac{log(27)}{log(5)}$, we can use a calculator to evaluate $log(27)$ and $log(5)$ individually, then take the ratio.
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