Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 18

Answer

$0,6$

Work Step by Step

1. By definition, from $log_2[(x-4)(x-2)]=3$, we have $(x-4)(x-2)=2^3\longrightarrow x^2-6x+8=8\longrightarrow x(x-6)=6 \longrightarrow x=0,6$ 2. Check the answers in the original equation and they both fit.
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