Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Test - Page 496: 23

$10\ sec$

1. Given $v(t)=176(1-e^{-0.18t})$, for $v=147\ ft/sec$, we have $176(1-e^{-0.18t})=147\longrightarrow 1-e^{-0.18t}=\frac{147}{176} \longrightarrow e^{-0.18t}=\frac{29}{176}$ 2. Take $ln$ on both sides to get $-0.18t=ln(\frac{29}{176})$ and $t=-\frac{ln(\frac{29}{176})}{0.18}\approx10\ sec$