Answer
$x_{1}=8;x_{2}=-1$
Work Step by Step
$\log _{2}\left( x-7\right) +\log _{2}x=3\Rightarrow \log _{2}\left( \left( x-7\right) x\right) =\log _{2}8$
$\Rightarrow x\left( x-7\right) =8\Rightarrow x^{2}-7x-8=0\Rightarrow \left( x-8\right) \left( x+1\right) =0\Rightarrow x_{1}=8;x_{2}=-1$