Answer
$-\dfrac {1995}{991}$
Work Step by Step
$\log \left( 9x+5\right) =3+\log \left( x+2\right) \Rightarrow \log _{10}\left( 9x+5\right) =\log _{10}1000+\log \left( x+2\right) $
$\Rightarrow \log _{10}\left( 9x+5\right) =\log _{10}\left( 1000\left( x+2\right) \right) \Rightarrow 9x+5=1000x+2000\Rightarrow x=-\dfrac {1995}{991}$