Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises: 57

Answer

$x_{1}=5;x_{2}=-20$

Work Step by Step

$\log x+\log \left( x+15\right) =2\Rightarrow \log _{10}\left( x\left( x+15\right) \right) =2$ $x\left( x+15\right) =10^{2}\Rightarrow x^{2}+15x-100=0$ $x_{1,2}=\dfrac {-b\pm \sqrt {b^{2}-4ac}}{2a}=\dfrac {-15\pm \sqrt {15^{2}-4\times 1\times \left( -100\right) }}{2}=\dfrac {-15\pm 25}{2}=-20; 5$
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