Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 74

Answer

$4$

Work Step by Step

$\ln \left( 5+4x\right) -\ln \left( 3+x\right) =\ln 3\Rightarrow \ln \dfrac {5+4x}{3+x}=\ln 3$ $\Rightarrow \dfrac {5+4x}{3+x}=3\Rightarrow 5+4x=9+3x\Rightarrow x=4$
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