Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 21

Answer

$\pm 2.146$

Work Step by Step

We need to take natural log of both sides , then the given expression can be written as: $\ln e^{x^2}=\ln 100 $ Apply logarithmic property : $\log a^ b=b \log a$ and $\ln e^a= a$ $x^2 =\ln 100$ Now, we will evaluate the result for $x$. Therefore, our answer is: $x =\pm \sqrt {\ln 100}=\pm 2.146$
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