Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 24

Answer

$x=0.347$

Work Step by Step

The given expression can be written as: $ e^{1-3x+5x}=2e $ This implies that $ e^{1+2x} =2e$ We need to take natural log of both sides and apply logarithmic property : $\log a^ b=b \log a$ . $2x \ln e=\ln 2$ Now, we will evaluate the result for $x$. $2x =0.693$ Therefore, our answer is: $x=0.347$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.