Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises: 61

Answer

$2$

Work Step by Step

$\log \left( x-10\right) -\log \left( x-6\right) =\log 2\Rightarrow \log \left( x-10\right) =\log 2+\log \left( x-6\right) \Rightarrow$ $ \log \left( x-10\right) =\log \left[ 2\times \left( x-6\right) \right] \Rightarrow x-10=2x-12\Rightarrow x=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.