Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 469: 31

Answer

$\{ 25.677\}$

Work Step by Step

Step 1. Rewrite the equation as $2(1.05)^x=7$ or $(1.05)^x=\frac{7}{2}$ Step 2. Take natural logarithm on both sides to get $x\ ln(1.05)=ln\frac{7}{2}$, thus $x=\frac{ln\frac{7}{2}}{ ln(1.05)}\approx25.677$ Step 3. Write answer in set form $\{ 25.677\}$
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