Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises: 55

Answer

$x_{1,2}=0,-8$

Work Step by Step

$\log _{2}\left( \left( 2x+8\right) \left( x+4\right) \right) =5\Rightarrow \left( 2x+8\right) \left( x+4\right) =2^{5}=32$ $\Rightarrow 2\left( x+4\right) ^{2}=32\Rightarrow \left( x+4\right) =\pm \sqrt {16}=\pm 4\Rightarrow x_{1,2}=0,-8$
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