Answer
$\frac{1}{24}$
Work Step by Step
Because $0\lt1/2$, by Equation (4): $\int_{0}^{1/2} t^2 dt=\frac{(\frac{1}{2})^3}{3}-\frac{0^3}{3}=\frac{\frac{1}{8}}{3}-\frac{0}{3}=\frac{1}{24}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 35
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