Answer
-1
Work Step by Step
$\int^{\sqrt 2}_{0}(t-\sqrt {2})dt=\int^{\sqrt 2}_{0}tdt- \sqrt {2}\int^{\sqrt 2} _{0}dt$
$=\frac{(\sqrt {2})^{2}}{2}-\sqrt {2}(\sqrt {2}-0)= \frac{2}{2}-2= -1$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 44
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