## University Calculus: Early Transcendentals (3rd Edition)

$-14$
According to Rule (1) in Table 5.4 : $\int_{3}^{1} 7dx=-\int_{1}^{3} 7dx$ Because $1\lt3$, by Equation (3): $-\int_{1}^{3} 7dx=-7\cdot(3-1)=-7\cdot2=-14$