University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises: 41

Answer

$-14$

Work Step by Step

According to Rule (1) in Table 5.4 : $\int_{3}^{1} 7dx=-\int_{1}^{3} 7dx$ Because $1\lt3$, by Equation (3): $-\int_{1}^{3} 7dx=-7\cdot(3-1)=-7\cdot2=-14$
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