Answer
$\frac{3}{2}(b^{2}-a^{2})$
Work Step by Step
Using equation (2), we have $\int^{b}_{a}3tdt=3\times[\frac{b^{2}}{2}-\frac{a^{2}}{2}]=3\times\frac{b^{2}-a^{2}}{2}$
$=\frac{3}{2}(b^{2}-a^{2})$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 26
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