Answer
$b^2$
Work Step by Step
$\int_{0}^{b} 2xdx=[x^2]_{0}^{b}=b^2-0^2=b^2$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 53
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