Answer
$\frac{7}{3}$
Work Step by Step
Using equation (4), we get
$\int^{\sqrt[3] 7}_{0}x^{2}dx=\frac{(\sqrt[3] 7)^{3}}{3}-\frac{0^{3}}{3}$
$=\frac{7}{3}-0= \frac{7}{3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 33
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