Answer
$9b^{3}$
Work Step by Step
We know that $\int^{b}_{0}x^{2}dx= \frac{b^{3}}{3}$
Then $\int^{3b}_{0}x^{2}dx= \frac{(3b)^{3}}{3}=\frac{27b^{3}}{3}=9b^{3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 40
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