Answer
0
Work Step by Step
$\int^{2}_{0}(3x^{2}+x-5)dx
$$=3\int^{2}_{0}x^{2}dx+\int^{2}_{0}xdx-5\int^{2}_{0}dx$
$=(3\times\frac{2^{3}}{3})+(\frac{2^{2}}{2})-(5\times2)$
$= 8+2-10= 0$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 49
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