Answer
a) 4
b) -4
Work Step by Step
a) $\int^{4}_{0}f(z)dz= \int^{3}_{0}f(z)dz+\int^{4}_{3}f(z)dz$
$⇒7=3+\int^{4}_{3}f(z)dz $
$⇒\int^{4}_{3}f(z)dz= 7-3=4 $.
b) $\int^{3}_{4}f(t)dt=\int^{3}_{4}f(z)dz= -\int^{4}_{3}f(z)dz$
$=-4$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 13
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