Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 3 - Determinants - 3.1 Exercises - Page 170: 37

Answer

$5A=\begin{bmatrix}15&5\\20&10\end{bmatrix}$ No: $\det 5A\neq5\det A$.

Work Step by Step

$5A=\begin{bmatrix}5\cdot3&5\cdot1\\5\cdot4&5\cdot2\end{bmatrix}=\begin{bmatrix}15&5\\20&10\end{bmatrix}$ $\det 5A=15\cdot10-5\cdot20=150-100=50$ $5\det A=5\begin{vmatrix}3&1\\4&2\end{vmatrix}=5(6-4)=10$
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